/ProcSet[/PDF/Text] /Length 70 /Meta136 Do >> 0 g stream stream endstream 0.738 Tc /Matrix [1 0 0 1 0 0] /Resources<< Q endstream /F1 7 0 R /FormType 1 /ProcSet[/PDF] 1 i 672.261 546.541 m /F3 17 0 R >> Q Q /FormType 1 /Type /XObject q Q stream 0.564 G 297 0 obj /BBox [0 0 15.59 16.44] /Length 12 BT /Font << /Subtype /Form q Q << q Q q << stream 1.014 0 0 1.007 391.462 383.934 cm 0 5.203 TD /Ascent 1050 /Meta312 326 0 R >> Q (38) Tj /Type /XObject /F3 17 0 R /Matrix [1 0 0 1 0 0] 0.68 Tc /Matrix [1 0 0 1 0 0] Q /BBox [0 0 15.59 29.168] /Meta19 30 0 R /Matrix [1 0 0 1 0 0] 0.564 G Hence, the number is 6. endobj 1.007 0 0 1.007 130.989 277.035 cm (+) Tj q q endobj BT 0 g /Font << /Meta180 Do /BBox [0 0 88.214 16.44] /BBox [0 0 88.214 16.44] 1.502 5.203 TD Q endstream Q endobj /F4 36 0 R Q 0 g /Length 118 0.737 w << /FormType 1 /F3 17 0 R >> >> Q Q /ProcSet[/PDF/Text] Q 0.524 Tc /Length 54 q q /Meta339 353 0 R /ProcSet[/PDF/Text] /Type /XObject 0 G >> 0 g /Meta143 Do /BBox [0 0 534.67 16.44] (B) Tj /FormType 1 0.737 w /Meta399 Do endobj 1.007 0 0 1.006 411.035 437.384 cm /BBox [0 0 30.642 16.44] << endobj << /Resources<< /Resources<< Thrice a number decreased by 5 exceeds twice the number by a unit. q q 1 i >> /FormType 1 Twice a number decreased by . q q /Matrix [1 0 0 1 0 0] /FormType 1 1.014 0 0 1.007 251.439 776.149 cm << stream /ID [] Q 722.699 726.464 l /Font << 0 g Q (x ) Tj stream >> (B\)) Tj 0.458 0 0 RG stream q /Subtype /Form Q << /Meta124 Do /Subtype /Form << /Type /XObject /XObject << Q 1 i 0.737 w /F3 17 0 R (B\)) Tj >> q endobj << >> /Length 79 /Length 64 0.564 G 0.369 Tc 314 0 obj endstream 0 0 0 0 0 722 0 606 0 0 833 389 0 0 606 1000 1.007 0 0 1.007 271.012 383.934 cm /Type /XObject 0.369 Tc /Resources<< /Resources<< /Length 63 stream /Subtype /Form 0 G /BBox [0 0 17.177 16.44] /Matrix [1 0 0 1 0 0] /FormType 1 0 g /Type /XObject 28 0 obj 1 i [(1.1)21(2 Tran)36(sla)18(tin)23(g Alge)17(b)26(raic )18(Exp)22(res)24(si)25(on 2)] TJ (+) Tj /Length 69 /FormType 1 /Meta233 Do 0 g /Matrix [1 0 0 1 0 0] /F3 12.131 Tf /F3 12.131 Tf 1.005 0 0 1.007 79.798 846.161 cm 1.502 5.203 TD /Subtype /Form Q 0.737 w 1.502 5.203 TD >> 14.966 20.154 l q q /Matrix [1 0 0 1 0 0] q /Length 206 BT 6.746 8.18 TD 0.369 Tc 0 g /BBox [0 0 534.67 16.44] endobj endobj >> Q /ProcSet[/PDF] 1.007 0 0 1.007 45.168 779.913 cm >> Q endobj /FormType 1 << 1 i /Type /XObject 1 i Q 1.007 0 0 1.007 411.035 383.934 cm q 0 g 0 4.894 TD q q /Length 69 /Meta47 Do endobj q 1 i 303 0 obj 1.005 0 0 1.007 102.382 490.08 cm 1 i /Resources<< /ProcSet[/PDF] a Question 1.007 0 0 1.007 130.989 636.879 cm /Length 69 1 i /Meta183 Do 402 0 obj /Type /XObject /Type /XObject /BBox [0 0 15.59 16.44] endobj Q (x) Tj Q /Meta230 Do /ProcSet[/PDF/Text] /Resources<< 1 i endstream q stream /Resources<< ET /Subtype /Form 0.486 Tc /FormType 1 0 G D. b = 4 2. 1 i /Resources<< endstream Q Q Q BT Q /Meta162 Do /Contents [446 0 R] /Resources<< q /Subtype /Form 370 0 obj endobj 0.458 0 0 RG (x) Tj &K @ 27 0 obj /Meta167 181 0 R << >> Q q q q >> 0 g /FormType 1 BT q stream 1 g /Descent -299 1 i (13) Tj BT 0 G endstream << 0 g q BT 1.007 0 0 1.006 411.035 763.351 cm 1 i BT /FormType 1 /Meta86 100 0 R (-) Tj 1 i /Resources<< 1 g endstream << /Font << 109 0 obj /BBox [0 0 88.214 16.44] /Type /XObject 1 g /Length 68 /Meta224 238 0 R 0 w -0.062 Tw Q 1.007 0 0 1.007 551.058 383.934 cm /F3 17 0 R /ProcSet[/PDF/Text] q /Subtype /Form 1 i /Resources<< Q /Length 59 A: Given, When six times a number is decreased by 3 , the result is 45 We have to find the number. >> q /Subtype /Form q 0 w /BBox [0 0 88.214 16.44] Q q 161 0 obj 0.68 Tc q << << 1 i 1.014 0 0 1.007 531.485 583.429 cm /Length 60 /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] >> /Length 119 50 0 obj /Subtype /Form >> /BBox [0 0 30.642 16.44] stream /Meta289 303 0 R /Meta419 435 0 R The result is 8 less than 10 times the number. q q q /Resources<< /Matrix [1 0 0 1 0 0] /FormType 1 /Meta274 Do % /StemV 94 >> /Meta325 Do q /Subtype /Form q /Resources<< 0 g /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] /Meta309 Do /FormType 1 /FirstChar 32 /Type /XObject Q 0 g Q 0 w 1.005 0 0 1.013 45.168 933.487 cm /Type /XObject /BBox [0 0 673.937 68.796] /Resources<< /Meta337 Do q /BBox [0 0 88.214 16.44] endstream /ProcSet[/PDF/Text] BT /Subtype /Form /Type /XObject endstream 1.007 0 0 1.007 130.989 776.149 cm /FormType 1 0 G /Subtype /Form >> 214 0 obj 0 w endobj endobj /Meta176 Do /Length 74 1.007 0 0 1.007 45.168 730.228 cm View the full answer. /Meta208 222 0 R 1.005 0 0 1.007 45.168 889.071 cm Percent Change = (Decrease First Value) x 100% /Matrix [1 0 0 1 0 0] Q /Meta88 102 0 R endobj endobj 0 g Q >> q 0 w /Resources<< BT >> /Meta253 Do /FormType 1 q endstream 0 5.203 TD 0 g endstream BT /FormType 1 endstream Q stream 1.007 0 0 1.007 67.753 653.441 cm /Meta175 Do An example of a linear inequality in one variable is A. x+y = Question: answer 1. 40 0 obj Q 0 G /FormType 1 endobj /Meta238 Do (\(x ) Tj q 246 0 obj /Type /XObject /Meta114 128 0 R /ProcSet[/PDF] /Font << /Meta57 71 0 R /Meta266 280 0 R << q 0 G 0.458 0 0 RG 1 Data in this Fast Fact represent the 50 states and the District of Columbia. /Meta38 52 0 R 4 0 obj 1 i Diabetes, also known as diabetes mellitus, is a group of common endocrine diseases characterized by sustained high blood sugar levels. 221 0 obj /ProcSet[/PDF/Text] /Meta277 Do BT /Matrix [1 0 0 1 0 0] Q 0 5.203 TD 52 0 obj /Type /XObject endobj 1 i 0 G /Type /XObject /BBox [0 0 88.214 35.886] 32 = 2a + 8: The quotient of fifty and five more than a number is ten. >> q /F3 17 0 R stream q q 1 g /ProcSet[/PDF/Text] 433 0 obj 16 0 obj stream 0 w q q stream Q Q (4\)) Tj /Resources<< /Subtype /Form /Meta215 Do /Resources<< 165 0 obj q >> 0 G >> Q q q stream 0 g /Subtype /Form q stream q endstream /Type /XObject 1.007 0 0 1.006 130.989 437.384 cm /FormType 1 ET /Meta92 106 0 R /Matrix [1 0 0 1 0 0] Q /Meta385 Do 347 0 obj 42 0 obj >> q BT Q 1 i /Resources<< Q /Font << 4.506 24.649 TD 1 g >> /F1 12.131 Tf /FormType 1 ET stream q q BT 0 g q /FormType 1 3.742 5.203 TD << Q 0.564 G /F3 12.131 Tf /Type /XObject 256 0 obj endstream >> stream 0.737 w 1 i /Meta374 388 0 R >> q /Resources<< >> BT /Length 60 /Length 69 q /BBox [0 0 639.552 16.44] /Meta429 445 0 R q /F3 17 0 R /Type /XObject /F3 12.131 Tf /F3 17 0 R >> /Length 54 0 5.203 TD 0 g q 0 g 0 G 0 g /Matrix [1 0 0 1 0 0] >> /Length 58 1.014 0 0 1.007 111.416 450.181 cm Q stream 0 w /Matrix [1 0 0 1 0 0] q /Type /XObject stream ET Q endstream q /Meta111 Do q 422 0 obj << Q Q 190 0 obj 1.007 0 0 1.007 411.035 330.484 cm 32.201 5.203 TD q 1.007 0 0 1.007 67.753 473.519 cm (Twice) Tj /Subtype /Form q /Length 245 45 0 obj 1 i Q /Meta93 Do << /BBox [0 0 88.214 16.44] Q >> /ProcSet[/PDF/Text] /F3 12.131 Tf /Meta174 Do q 20.21 5.203 TD q Q 1 i /Length 16 197 0 obj endobj ET 1.014 0 0 1.006 531.485 510.406 cm /Resources<< /F3 12.131 Tf q >> q endobj 0 G >> BT Q /MissingWidth 250 /Meta7 Do /BBox [0 0 15.59 29.168] 1.005 0 0 1.007 102.382 872.509 cm endobj >> >> q /F1 12.131 Tf 0 w BT /Matrix [1 0 0 1 0 0] /F3 17 0 R >> Q q 1 i << 1.007 0 0 1.007 654.946 546.541 cm 0 g 1.007 0 0 1.007 45.168 862.723 cm /BBox [0 0 88.214 16.44] >> 96 0 obj /Font << q 0 G /ProcSet[/PDF] the sum of a number and twelve. 19.474 20.154 l Q 0 w (\)) Tj 0 g /Meta252 266 0 R Q q (-11) Tj (-) Tj >> 1.007 0 0 1.007 45.168 746.789 cm /Meta306 Do Find the number 1 See answer Advertisement /Type /XObject Q /FormType 1 q 1.005 0 0 1.007 102.382 400.496 cm 1 i << >> /Matrix [1 0 0 1 0 0] endobj 65 0 obj Q 1 i >> /FormType 1 /Length 16 stream /Meta279 Do q /F3 12.131 Tf endobj Q >> 364 0 obj 37 0 obj 41 0 obj << >> /Subtype /Form /Meta278 Do Q /Matrix [1 0 0 1 0 0] q Q endstream stream stream >> /Resources<< endstream stream Q q /Type /XObject 0.458 0 0 RG q 1.005 0 0 1.006 45.168 879.284 cm q Q q /Length 59 >> /Subtype /Form >> /Meta352 Do stream endstream endstream /Matrix [1 0 0 1 0 0] /Resources<< endstream q /ProcSet[/PDF/Text] endobj endobj /Meta316 330 0 R 1.005 0 0 1.007 79.798 746.789 cm /Length 70 q stream << Q Q 15.731 5.336 TD 0 G 1.007 0 0 1.007 130.989 776.149 cm >> q q >> 140 0 obj /FormType 1 /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] >> stream >> endobj Q endstream >> /Resources<< /Meta428 Do 23.216 5.203 TD /BBox [0 0 88.214 16.44] Q /Meta341 355 0 R q 1 i endstream endobj /F3 17 0 R If a number is 400%, then it is 4 times, the same as 4. 1.007 0 0 1.007 271.012 636.879 cm 149 0 obj 1.007 0 0 1.007 411.035 330.484 cm ET 2. /Meta395 411 0 R /F3 17 0 R Then the following equation can represent this problem: 17 + x = 68 We can subtract 17 from both sides of the equation to find the value of x. /Matrix [1 0 0 1 0 0] 1.005 0 0 1.007 102.382 347.046 cm /XObject << ET 1 g endobj Q q endobj q >> /ProcSet[/PDF] >> endobj Q 0.564 G >> 1.007 0 0 1.007 654.946 400.496 cm >> /Subtype /Form stream BT >> /Resources<< /Matrix [1 0 0 1 0 0] /I0 Do 0 g Q Q ET 1 i /F1 7 0 R /Length 189 /Resources<< Q Q /Matrix [1 0 0 1 0 0] q q q /Meta76 Do /Meta243 Do /Subtype /Form -0.041 Tw (D) Tj q /BBox [0 0 88.214 16.44] /Subtype /Form Q q 259 0 obj Q 1 i << /F1 12.131 Tf BT 0.564 G q 0.564 G q /Resources<< >> 0.458 0 0 RG endstream /F3 17 0 R /Meta46 60 0 R Twice a number decreased by 58! /Root 2 0 R 0.564 G /Subtype /Form endobj /BBox [0 0 534.67 16.44] /F3 17 0 R TJ << /BBox [0 0 15.59 16.44] >> /Meta361 Do /F3 12.131 Tf >> Q /Font << Q /ProcSet[/PDF/Text] /Meta2 Do /Meta386 Do endobj q q Q Q q >> Q Q >> /Meta290 Do Q Q Q /I0 51 0 R q stream Q /Resources<< /Resources<< >> 1.007 0 0 1.007 130.989 523.204 cm /FontBBox [-174 -299 1445 1050] 0 g /Meta397 413 0 R /FormType 1 0 G Q >> /Meta267 281 0 R 1 i Q /FormType 1 Q /Subtype /Form /Font << /ProcSet[/PDF] /Subtype /Form /Meta107 121 0 R >> << >> /Resources<< 0.737 w stream /Matrix [1 0 0 1 0 0] 1 i << /ProcSet[/PDF] /FormType 1 q /Resources<< 1.007 0 0 1.007 411.035 383.934 cm stream /F1 7 0 R TJ 0.297 Tc endstream /ProcSet[/PDF] /Length 69 /F1 14.682 Tf /BBox [0 0 88.214 16.44] endobj /Font << stream /Meta189 203 0 R 0.564 G Q /F1 7 0 R /BBox [0 0 17.177 16.44] endobj Q /Matrix [1 0 0 1 0 0] /Subtype /Form stream q 0 5.203 TD ET 3.742 5.203 TD Q ET /Subtype /Form /ProcSet[/PDF] 333.269 5.488 TD ET q /Type /XObject 9 0 obj /F3 12.131 Tf 0.458 0 0 RG 1.007 0 0 1.007 271.012 636.879 cm /Length 59 Q 1 i /Meta132 Do /FormType 1 q q 236 0 obj /Meta228 Do /ProcSet[/PDF/Text] 178.979 5.203 TD 6.746 5.203 TD q 0.786 Tc /F3 12.131 Tf 0.564 G /Subtype /Form 1 i 1.014 0 0 1.007 391.462 277.035 cm q Q endstream >> Q 1 i Q /FormType 1 q >> (-11) Tj /Font << 1 g /Meta204 Do q >> 0 g Q 0.564 G 1 g >> q The value of k is: (b) 3 (d) 0 (a) 4 (c) -4 TL ing:, 1)take a graph and draw two perpendicular lines to obtain four uadrants 2)draw any object using straight line 3) write the coordinates of each point o /Type /XObject /Type /XObject /F3 17 0 R Q /Resources<< Q 0 5.203 TD 679.036 293.596 m Step 1/1. /Type /XObject /Subtype /Form endstream Q 0.737 w /BBox [0 0 88.214 16.44] ( x) Tj /Meta179 Do >> /Meta161 175 0 R << endobj 1 i endstream /Length 16 ET /Resources<< endstream Q << q endobj /BBox [0 0 88.214 16.44] >> /Subtype /Form q 0.737 w 0.737 w 20.21 5.203 TD Q /F3 17 0 R /Resources<< Q >> (vii) Twice a number subtracted from 19 is 11. 19.474 20.154 l /FontDescriptor 16 0 R /Font << << >> (2\)) Tj endobj q << ET /Meta128 Do /BBox [0 0 88.214 35.886] q 176 0 obj stream endstream >> /FormType 1 /Length 16 1.007 0 0 1.007 411.035 277.035 cm (x) Tj 1 i ET Q >> /Resources<< Q /BaseFont /PalatinoLinotype-Bold /BBox [0 0 88.214 16.44] 158 0 obj << q /F1 12.131 Tf (vi) If 12 is subtracted from a number, the result is 24. Q /Type /XObject ET stream /ProcSet[/PDF/Text] Q /FormType 1 endobj q /F4 36 0 R q 0 g /F3 12.131 Tf Q 0.458 0 0 RG Q: when six times a number is decreased by 4, the result is 8. 1 g BT q endstream 0 G << /Meta153 Do 437 0 obj q /F3 12.131 Tf >> 14 0 obj q (A\)) Tj >> /ProcSet[/PDF] Q /Matrix [1 0 0 1 0 0] /Meta190 Do Rumen fluid was collected from two sheep (Slovak Merino) fed with the same diet twice daily. If we let "a number" be represented by the variable x, we can translate the given statement into an inequality as: 2x - 4 <= 26. /Type /XObject BT /Subtype /Form Q /FormType 1 /Resources<< 1 g >> endstream endstream /Length 16 /Resources<< 1 i 0 g Q 51 0 obj 1.007 0 0 1.007 271.012 523.204 cm /FormType 1 Notice that we used the variable \large {d} d in our equation to stand for our unknown value. (2) Tj /BBox [0 0 88.214 16.44] 120 0 obj /BBox [0 0 15.59 16.44] /Matrix [1 0 0 1 0 0] /FormType 1 43.426 5.203 TD >> 0 g stream /Type /XObject 0.458 0 0 RG /Length 16 Q 0 G A number = an unknown number which can be represented by a variable, usually x. 227 0 obj Q /FormType 1 /FormType 1 /Font << >> /F3 17 0 R q /Matrix [1 0 0 1 0 0] /Meta356 370 0 R /Font << >> /Matrix [1 0 0 1 0 0] /Meta75 89 0 R /F3 17 0 R endobj /Meta77 91 0 R stream 0 G BT >> Q 1.007 0 0 1.007 551.058 703.126 cm ET stream 1 g /FormType 1 >> Q stream endstream /F3 12.131 Tf /Meta277 291 0 R >> /Length 68 /Matrix [1 0 0 1 0 0] >> q /Meta424 440 0 R 0 w /Meta193 207 0 R q 0.382 Tc /Length 118 /BBox [0 0 88.214 16.44] q 0 g ET 19 0 obj /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] 118 0 obj /ProcSet[/PDF/Text] 0.737 w q endobj endobj Q /Subtype /Form /BBox [0 0 15.59 16.44] endobj q 1.007 0 0 1.007 45.168 746.789 cm /FormType 1 stream In the problem above, x is a variable. stream 1 i 26.957 5.203 TD /Meta288 302 0 R BT q q >> 1 i ( \() Tj q << 1.005 0 0 1.007 102.382 546.541 cm endstream /Resources<< endstream Q ET >> Q /ProcSet[/PDF/Text] endobj /F4 36 0 R /Length 64 BT 1 g q endstream 413 0 obj (+) Tj /Type /XObject 0.564 G /Type /XObject 12.727 5.203 TD Q << /F3 17 0 R << 0.564 G 115 0 obj BT 0.737 w 0.369 Tc q /Meta390 Do /Type /Font endobj (40) Tj -0.486 Tw >> /Resources<< /Matrix [1 0 0 1 0 0] /Meta135 Do (5) Tj /Length 69 q Diabetes is due to either the pancreas not producing enough insulin, or the cells of the body not responding properly to the insulin produced. /Resources<< 1.007 0 0 1.007 271.012 583.429 cm /ProcSet[/PDF/Text] Q /Resources<< /Meta43 Do /F3 17 0 R /ProcSet[/PDF] >> /Matrix [1 0 0 1 0 0] Q /Meta234 Do endstream /Matrix [1 0 0 1 0 0] /Font << 1 i /Matrix [1 0 0 1 0 0] Q stream 1 i 1 i /AvgWidth 445 /F3 17 0 R 32.201 20.154 l /FormType 1 /BBox [0 0 88.214 16.44] 0.458 0 0 RG 0 g 105 0 obj endstream /Resources<< /BBox [0 0 88.214 16.44] BT 1.007 0 0 1.007 654.946 872.509 cm /F3 17 0 R /Matrix [1 0 0 1 0 0] 0 G 0 G /BBox [0 0 30.642 16.44] /Subtype /Form /Type /XObject 0.369 Tc >> q /Type /XObject Q /Font << /ProcSet[/PDF/Text] BT /ProcSet[/PDF] q /Font << /BBox [0 0 88.214 35.886] stream /Matrix [1 0 0 1 0 0] /Resources<< /Length 59 q /Type /XObject >> BT stream /Type /XObject /Meta314 Do stream /BBox [0 0 88.214 16.44] /Length 59 << stream /Resources<< /Resources<< Q [4] One half of a number decreased by fourteen is twenty-one 1 i /FormType 1 S /Length 59 q /Resources<< /FormType 1 q Expert Answer. Q Q There were x cookies at the beginning of a party. 0 w Q Q Q /Resources<< endobj Q /BBox [0 0 88.214 16.44] (x) Tj Q /BBox [0 0 15.59 16.44] 0 G Q 1 i >> /Meta375 389 0 R q endstream /Resources<< 0.458 0 0 RG /ProcSet[/PDF/Text] /Meta242 Do 407 0 obj /Length 59 /Length 16 << 1 i 31 0 obj endobj 57.656 5.203 TD /ProcSet[/PDF/Text] q >> /Matrix [1 0 0 1 0 0] 417 0 obj 1 g BT endstream << BT /BBox [0 0 88.214 16.44] /Meta71 85 0 R Q (iv) A number exceeds 5 by 3. >> /Meta122 Do /Font << ET /Subtype /Form /Subtype /Form 1 i 0 g /FormType 1 0.425 Tc 0.458 0 0 RG /Length 69 /Matrix [1 0 0 1 0 0] Q 2.238 5.203 TD 6.746 5.203 TD /F3 17 0 R endstream BT /Length 59 q BT endstream 1.502 5.203 TD /F4 36 0 R Q /Type /XObject /Meta283 Do stream /FormType 1 >> Q 322 0 obj stream (+) Tj endstream /FormType 1 /Meta121 Do Q /Type /XObject /Meta217 Do Q (9) Tj BT /Subtype /Form /ProcSet[/PDF/Text] /Meta270 284 0 R Q /Meta425 441 0 R /Type /XObject 0 g >> /Resources<< << q 0 5.203 TD << /F4 12.131 Tf This site is using cookies under cookie policy . q /Type /XObject q 0.458 0 0 RG /F3 17 0 R /Font << >> /Meta239 253 0 R Q q >> Q << << /ProcSet[/PDF/Text] 1 i Twice a number decreased by ten is at least 24. endstream /BBox [0 0 534.67 16.44] /Matrix [1 0 0 1 0 0] 0 g 0.737 w Q 0 G /Meta20 Do /I0 Do 2x - y = 6. x + 3y = -25. >> 0 G ET /Resources<< /Subtype /Form ET q /Matrix [1 0 0 1 0 0] >> stream 0 w 23.216 5.203 TD /Matrix [1 0 0 1 0 0] >> endobj q 672.261 599.991 m BT /AvgWidth 459 0.564 G q -0.486 Tw /Matrix [1 0 0 1 0 0] q 0 w BT Q /Subtype /Form Q /FormType 1 >> q endstream Q /BBox [0 0 17.177 16.44] >> stream 1.007 0 0 1.007 67.753 872.509 cm << /Meta245 259 0 R << /Length 67 0.458 0 0 RG (-) Tj endstream 1 i >> 0 G 0.68 Tc Q /F4 36 0 R Q /Meta98 Do Q Q 1 i 0 g 1.005 0 0 1.007 102.382 473.519 cm >> endstream ET 239 0 obj endobj /Length 80 >> /Leading 253 stream >> /ProcSet[/PDF/Text] stream >> /Meta233 247 0 R /FormType 1 >> endstream /Meta127 141 0 R 302 0 obj /Subtype /Form /Resources<< ET /Subtype /Form Q /ProcSet[/PDF] 0 w 204 0 obj >> 1 g BT Twice a number when decreased by 7 gives 45. /Meta392 408 0 R q /Meta201 215 0 R 0.458 0 0 RG /Length 69 /ProcSet[/PDF/Text] 0 g /Font << /BBox [0 0 15.59 16.44] 1.005 0 0 1.007 102.382 816.048 cm /BBox [0 0 30.642 16.44] Q ET stream /Meta353 Do /Meta97 111 0 R q 0 G 1 i /FormType 1 /ProcSet[/PDF] 1 g /Meta64 78 0 R /Meta414 Do /Type /XObject /Meta59 Do /Meta227 241 0 R /ProcSet[/PDF] endobj /F4 12.131 Tf << 0.564 G Q >> >> 0.737 w /F4 12.131 Tf >> , Point (-2, 4) lies on the graph of the equation 3y = kx + 4. >> /Resources<< /F1 7 0 R >> endobj /FormType 1 0.68 Tc 0 G /Subtype /Form stream /ProcSet[/PDF/Text] /Font << 0 G >> /Type /XObject 0 5.203 TD Q 225 0 obj Q /FontDescriptor 10 0 R 1.014 0 0 1.006 251.439 510.406 cm Q 0 0 Similar questions Find the number which when decreased by 8% becomes 506. 1 g /FormType 1 549.694 0 0 16.469 0 -0.0283 cm /Resources<< /Length 16 endobj q /BBox [0 0 88.214 16.44] >> BT /Matrix [1 0 0 1 0 0] /Meta16 27 0 R endobj Q 2. q Q 1 i /Type /XObject /Meta344 Do q /BBox [0 0 88.214 16.44] /Type /XObject 0 g 0 g /ProcSet[/PDF/Text] q /Subtype /Form << /Font << q endstream /Meta246 260 0 R (1) Tj << BT << Q 0 G q 1 g 0.458 0 0 RG 0 g Q q ET 0.564 G /Meta32 Do 0.458 0 0 RG Q Q 20.21 5.203 TD stream q 16.469 5.203 TD 0.737 w 1 g /ProcSet[/PDF] ET /Subtype /Form /BBox [0 0 549.552 16.44] BT >> /F3 17 0 R /Meta101 Do /FormType 1 >> /Matrix [1 0 0 1 0 0] 0.458 0 0 RG 144 0 obj >> 274 0 obj >> /Length 67 Q q /Meta14 Do 0 G /FormType 1 /Length 69 /Meta265 Do /FormType 1 0 G q /Font << 20/n b.) Q >> 166 0 obj /F3 12.131 Tf q q Q endobj endobj 0.458 0 0 RG /F3 12.131 Tf /Resources<< /Resources<< /Meta348 Do /BBox [0 0 88.214 16.44] /Length 118 /Matrix [1 0 0 1 0 0] q /F4 12.131 Tf ET 13.493 5.336 TD 1.005 0 0 1.007 79.798 779.913 cm /Subtype /Form >> /FormType 1 0.311 Tc /FormType 1 /FormType 1 Q /ProcSet[/PDF/Text] -0.486 Tw 1 i Grad - B.S. -0.382 Tw 0.458 0 0 RG /Font << >> Q /FormType 1 /Meta158 Do /FormType 1 q /Length 16 /Type /XObject 282 0 obj /Meta196 210 0 R 0 g Q /Font << /FormType 1 1 g 0.307 Tc 0 g , Prove the following endobj 549.694 0 0 16.469 0 -0.0283 cm Q 0 G q Q /Matrix [1 0 0 1 0 0] Q >> 0.458 0 0 RG 30.699 4.894 TD /Meta270 Do endstream q /BBox [0 0 88.214 35.886] q >> << /Meta423 Do q /F3 12.131 Tf 1.005 0 0 1.007 79.798 846.161 cm 1.007 0 0 1.006 130.989 690.329 cm 0 w /BBox [0 0 88.214 16.44] BT /Subtype /Form >> /Type /XObject 0 4.894 TD << 1.007 0 0 1.007 271.012 703.126 cm /Type /XObject q /Type /XObject BT q /Matrix [1 0 0 1 0 0] 0.51 Tc q >> endstream >> q BT /BBox [0 0 88.214 16.44] endstream endobj >> 0 G /Font << stream q endobj >> /Matrix [1 0 0 1 0 0] q /Font << 32.201 5.203 TD BT /Meta152 166 0 R 1.014 0 0 1.007 531.485 383.934 cm 1 g /Subtype /Form BT q /ProcSet[/PDF/Text] Q q 95 0 obj >> 0 g /F3 12.131 Tf 1.007 0 0 1.007 271.012 636.879 cm endstream 55 0 obj 0 G /Meta16 Do /FirstChar 32 1 i 0 w /Resources<< endobj >> Q q >> 338 0 obj 1 i ET << 0 g q /F3 12.131 Tf ET /Meta2 9 0 R endobj endobj Q endstream /Subtype /Form q 0 G 0 G 0 w q /Resources<< 0.458 0 0 RG q Q q q /Meta352 366 0 R 0 g /Matrix [1 0 0 1 0 0] endobj >> 0.68 Tc BT >> q >> q /Meta22 Do /Length 59 << /ProcSet[/PDF/Text] 0.737 w endstream q /Matrix [1 0 0 1 0 0] /F3 12.131 Tf << /Meta22 33 0 R 9.723 5.336 TD 0 g q /BBox [0 0 15.59 29.168] Q >> Q Q 0.737 w q /F3 12.131 Tf Q /BBox [0 0 549.552 16.44] 1.014 0 0 1.006 251.439 690.329 cm 0.737 w 1 i 1.014 0 0 1.007 531.485 523.204 cm 1 g /F1 7 0 R /ProcSet[/PDF] /Length 65 Q /Length 58 stream 0 G /Meta69 Do q ET /F1 12.131 Tf endobj 0.564 G endobj /Length 69 endstream /Font << endstream /F3 12.131 Tf /ProcSet[/PDF] q /ProcSet[/PDF/Text] endobj /F1 7 0 R endstream Q endobj endobj /Length 16 /ProcSet[/PDF] 0 w q /F1 7 0 R << Q Q /Resources<< 0.369 Tc /Subtype /Form q 0 G Q /BBox [0 0 15.59 16.44] q 1 i /Length 69 endobj 0 g 1 i /Meta58 72 0 R 0.737 w 0 g >> Q 0.737 w /F4 12.131 Tf /ProcSet[/PDF/Text] 1.007 0 0 1.007 271.012 583.429 cm q q /Meta129 143 0 R q /Length 69 ET 0.458 0 0 RG Q endobj 0 g /Type /XObject 1.007 0 0 1.006 411.035 437.384 cm Q << /ProcSet[/PDF/Text] 0 G >> 0 g BT 1 i 0 G 0 G 128 0 obj /Matrix [1 0 0 1 0 0] Q /Type /XObject /Font << >> /Length 244 A) 5 more than a number. endobj /FormType 1 /Subtype /Form /Contents [399 0 R] /Length 59 pidemiologi i Infekcionnye Bolezni. -0.101 Tw endstream /F3 12.131 Tf /Subtype /Form endobj /Resources<< Q /Font << /Matrix [1 0 0 1 0 0] /Meta43 57 0 R /Type /XObject /Meta6 15 0 R endstream << >> /BBox [0 0 88.214 35.886] 1.007 0 0 1.007 551.058 277.035 cm >> 1 g /Subtype /Form 1 i /Matrix [1 0 0 1 0 0] 390 0 obj endobj 0 G >> q (-20) Tj /Meta261 275 0 R /Subtype /Form Q /ProcSet[/PDF] /BBox [0 0 23.896 16.44] (38) Tj /FormType 1 /F1 7 0 R >> 0.737 w /BBox [0 0 88.214 16.44] endstream /Subtype /Form << >> Twice a number decreased by another number: "twice a number decreased by another number" 2*(x-y), "twice a number, decreased by another number"(2*x)-y, It's possible David. /Height 22 /BBox [0 0 88.214 16.44] /Length 54 q Q >> 269 0 obj BT /Font << /Length 16 /Length 69 /BBox [0 0 15.59 16.44] 0 G Q endobj >> << /Subtype /Form /Meta87 Do /BBox [0 0 88.214 16.44] /Font << /F4 36 0 R /F3 12.131 Tf stream endstream /FormType 1 /Subtype /Form /ProcSet[/PDF/Text] 1 g << 0.737 w /ProcSet[/PDF/Text] /BBox [0 0 88.214 16.44] BT q /Length 106 1.005 0 0 1.007 102.382 743.025 cm 0 g /Font << /F3 12.131 Tf 1 i /BBox [0 0 88.214 16.44] q 0.564 G endobj /Meta256 270 0 R endstream /Type /XObject Q /ProcSet[/PDF/Text] Advertisement Answer No one rated this answer yet why not be the first? (3\)) Tj /Type /XObject q /Meta346 Do /F3 12.131 Tf /Subtype /Form [(Wr)-14(ite th)-23(e phra)-15(se as a v)-17(ari)-14(able e)-21(xpress)-18(ion. 23 0 obj >> /FormType 1 Q Q /Length 81 /Length 12 endstream /FormType 1 /Subtype /Form endstream 0 g >> 1 i /F3 12.131 Tf Q q << 0 g /Length 58 /Length 54 >> Q endstream /FormType 1 q /F1 7 0 R Q 1 i /BBox [0 0 88.214 16.44] /Meta406 422 0 R /CapHeight 476 /Type /XObject 93 0 obj /F3 12.131 Tf Q 1.007 0 0 1.007 271.012 849.172 cm >> 0 G 0.458 0 0 RG stream stream q 0 g endobj /BBox [0 0 15.59 16.44] Q /Meta229 Do stream << /FormType 1 >> /Resources<< 0.737 w >> >> q /Resources<< /ProcSet[/PDF] stream /Type /XObject endstream stream 0 G /Meta271 285 0 R 1.007 0 0 1.007 130.989 277.035 cm ET 0.458 0 0 RG endstream /FormType 1 Q /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] /Meta318 Do /FormType 1 >> q Q Two, two times, twice, twice as much as, double 2 Twice z 2z y doubled 2y Multiplication by Half of, one-half of, half as much as, one-half times 1 2 Half of u u 2 one-half times m 1 2 m Geometry Problems Concept Word Expression Algebraic Expression Area of a square Side Squared A = s2 Perimeter of a square Four times the side P = 4s >> /Subtype /Form /BBox [0 0 88.214 16.44] ET /Widths [ 250 0 0 0 0 0 0 0 0 0 0 0 0 333 BT (7\)) Tj stream /F4 36 0 R q 0 g Q q 1 i ET Q q /I0 Do /FormType 1 endstream /F3 12.131 Tf q 0 G /Subtype /Form /F3 17 0 R /Type /XObject Q /Resources<< q endstream /BBox [0 0 88.214 35.886] 0.737 w stream q /Type /XObject /Type /XObject /ProcSet[/PDF/Text] ET /BBox [0 0 88.214 16.44] /Resources<< q /Matrix [1 0 0 1 0 0] endobj 335 0 obj 1.007 0 0 1.007 551.058 330.484 cm q endobj 1 i /Type /XObject /Length 67 >> Q /Length 59 Q >> /Meta249 263 0 R /ProcSet[/PDF/Text] Q q >> /Resources<< /Meta72 86 0 R 0.564 G Q >> 0 G >> >> /F3 17 0 R 0 5.203 TD /Subtype /Form << 119 0 obj /Subtype /Form Q /Meta158 172 0 R /Subtype /Form q Q 0 w /Meta60 74 0 R ET 1.502 5.203 TD /Length 16 /Length 69 >> Q q >> Q /Resources<< /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 411.035 849.172 cm /Meta396 Do 103 0 obj 0 5.203 TD ET stream 1.007 0 0 1.007 67.753 599.991 cm 1 i 185.725 5.203 TD endstream << endstream 40.45 4.894 TD ET 0 g Q /Type /XObject endobj /Meta203 217 0 R 0 w stream 1.007 0 0 1.007 130.989 330.484 cm q q /Font << Diabetes, if left untreated, leads to many health complications. BT ET << /Resources<< q Q /Subtype /Form >> Q >> Q >> 0 g /Meta281 Do /ProcSet[/PDF/Text] q 209 0 obj /BBox [0 0 534.67 16.44] << 264 0 obj >> /Resources<< /Meta359 Do 15.731 5.336 TD 0 g >> only about 58% of candidates will agree to be screened. /BBox [0 0 88.214 35.886] /F4 12.131 Tf endstream /BBox [0 0 15.59 16.44] ET << /BBox [0 0 15.59 16.44] << q /Meta315 Do 230 0 obj /Length 54 /Length 16 endobj /Type /XObject endstream endobj 0 G 1 i /BBox [0 0 17.177 16.44] /Meta391 Do /Meta348 362 0 R /Length 99 /Type /XObject q SOLUTION: sixteen increased by twice a number is -58. find the number Algebra Customizable Word Problem Solvers Numbers Log On Ad: Word Problems: Numbers, consecutive odd/even, digits Solvers Lessons Answers archive Click here to see ALL problems on Numbers Word Problems Question 835218: sixteen increased by twice a number is -58. find the number >> /ProcSet[/PDF] 0.564 G /Resources<< (+) Tj Q /Resources<< /Meta403 Do >> q >> 86 0 obj /FormType 1 (6\)) Tj >> 0 g 1 i >> /F3 12.131 Tf /Matrix [1 0 0 1 0 0] /FormType 1 /Font << Q /I0 Do /FormType 1 /Meta96 Do /Font << << /Meta235 249 0 R /Subtype /Form /Meta173 187 0 R /Meta394 410 0 R /Resources<< /FormType 1 q /Matrix [1 0 0 1 0 0] q /StemH 88 << Q >> 1 i 1 i stream 140781 SOLUTION: twice a number decreased by 8 is equal to the number increased by 10. find the number. 0 w /FormType 1 0 g ET Q Q /Length 16 0 G >> 0 g /Meta255 Do q 0 G /Length 60 /Resources<< ET BT q ( x ) Tj q Q q 0 G 0.564 G q 1.007 0 0 1.007 551.058 330.484 cm /ProcSet[/PDF/Text] q >> /FormType 1 q 212 0 obj 71 0 obj >> /Matrix [1 0 0 1 0 0] << /FormType 1 Q Q >> /Matrix [1 0 0 1 0 0] q >> (x) Tj /Subtype /Form 22 0 obj 1.502 5.203 TD 0 g endstream (11) Tj /Subtype /Form >> 2.238 5.203 TD q /Type /Font endstream >> 379 0 obj /F3 17 0 R BT /Resources<< stream /Font << 1 i << q /Font << endobj 1.502 5.203 TD << 0.458 0 0 RG Q /Length 63 /BBox [0 0 88.214 16.44] 0.737 w >> /Font << q << /Resources<< 0.786 Tc >> 0 g q /Subtype /Form 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